Photocoupler

A Samsung UA55C6200UF suddenly shuts down during viewing, the red light flashes silently, and the relay rings once every 5 seconds.
After the door-to-door inspection of the skinny monkey, the maintenance fee is about 1,200 yuan. The user refused to repair and gave me the accessories.
Nothing to open up research research at night. Check the information on the Internet and check only the power board drawings and some maintenance procedures.
Samsung UA55C6200UF_BN44-00359A power circuit diagram.pdf

Measuring STBY power supply 5.2V is always normal, the power board standby control voltage is reduced by 1.5V per second, and the power board output 5.3V, 12V, 17V also changes.

Unplug the lamp line, disconnect the logic board, and press the button.

In the data, the 18P connection backlight that unplugs the power board to the motherboard should be lit. This is not the case. After unplugging, the main power supply does not work and the backlight does not light up.

Remove the power board and observe that the pull-up resistor RB852 of the standby control terminal is not installed. Take a 10K resistor welding, and the power-on backlight will light up. The output of the main power supply is normal. There is no problem with the power board.

The recovery circuit is energized to repair the motherboard, and the relay is still ringing. After 10 minutes, the temperature of each chip is found to be only one (the red frame below) is slightly warm, and the other is cold.
1.jpg

Obviously, the other chips are not working, and there is no possibility of power supply. I can't find the drawings and materials on the motherboard, I can only find the repairs myself.

Some people say that the brush machine does not start at all.

Continue to stroke and find that IC1011 temperature is too high, about 60 degrees.
2.JPG

IC1011 printed SOZ JY2, no information found. Careful observation of the surrounding wiring should be a power control tube or voltage regulator, measuring 1 foot 5.2V, 2 feet grounded, 3 feet 0.2V unstable, other feet without voltage. The external pin 3 has two inductors and several capacitors, which should be the output. The power-off measurement of the 3-pin ground resistance is almost zero. Blow down the two inductors of BD1042 and BD1131. Then measure the resistance of the 3 feet to the ground is very large, and the resistance of the right end of the BD1131 to the ground is 0. The BD1042 is powered on, and the 3-pin output is 3.3V. It is confirmed that IC1011 is a voltage regulator IC.
The next step is to eliminate the short circuit problem. Find a section of 18650 lithium battery, the negative pole is pressed in the high frequency head casing, and the positive pole is connected to the pen line to the right end of the BD1131. It immediately finds that a blue smoke rises from the C7413. Look for an approximate capacitor replacement, power on the backlight to light up, the sweet start music sounds............

This high current roast chicken method solves the component short circuit problem is relatively simple and effective, but it should be noted that the voltage used should not be too high to be lower than the normal working voltage of the circuit, but the higher current output capability, generally more than 3V The circuit chip filter capacitor is short-circuited. It is also faster to change your eyes. It has been found that the smoke and discoloration are abnormally powered off immediately, so as to avoid the copper foil burning.

I hope this article can give you some inspiration, thank you for watching.


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